A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O and 
. The distance PO is equal to
Text Solution
Verified by ExpertsThe correct answer is:
A
By using 
Where 
u = – OP, v = OQ
Hence 
⇒ ⇒ 
⇒ ⇒ OP = 5 R
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